Write an equation perpendicular to 5x+6y=18 that passes through the point (10,7)

Here, we are required to write an equation perpendicular to 5x + 6y = 18.

6x - 5y = 25.

Therefore, slope of equation 5x + 6y = 18 is -5/6.

Therefore, m1m2 = -1

Therefore, the slope of the required line, m2 is;

m2 = 6/5

Therefore, the equation of a line perpendicular to the equation 5x+6y=18 and passes through the point (10,7) is given as;

6/5 = (y - 7)/(x - 10).

By cross product; we have;

6x - 60 = 5y - 35

6x - 5y = 25.

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Step-by-step explanation:

6y = -5x + 18

y = -5/6x + 3

perp slope: 6/5

y - 7 = 6/5(x - 10)

y - 7 = 6/5x - 12

y = 6/5x - 5

answer: 590

step-by-step explanation:

x=half

step-by-step explanation: