The mean rate for cable with Internet from a sample of households was $106.50 per month with a standard deviation of $3.85 per month. Assuming the data set has a normal distribution, estimate the percent of households with rates from $100 to $115.

The percent of households with rates from $100 to $115. is      94.1%

Step-by-step explanation:

From  the question we are told that  

   The  mean rate is $ 106.50  per month

    The standard deviation is  $3.85

Let the lower rate be  $100

Let the higher rate  be  $ 115

Assumed from the question  that the data set is normally

The  estimate of the percent of households with rates from $100 to $115. is mathematically represented as

here x is a random value rate  which lies between the higher rate and the lower rate so

Where  

Where z is the standardized value of  x

So

Now  from the z table we obtain that

    94.1%

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step-by-step explanation: im watching dbz and eating popcorn leave meh alone