What is the quotient of the rational expression below x^2-25/x-11÷ x^2+10x+25/4x-44

The quotient is 4x-20/x+5

Step-by-step explanation:

The quotient is simply the result of the division

Through factorization, can express x^2 -25 as (x-5)(x+5)

Also x^2 + 10x + 25 as (x+5)(x+5)

and lastly 4x-44 as 4(x-11)

Now when we divide, the numerator of the second fraction will come down while the denominator goes up;

So we have ;

x^-25/x-11 * 4x-44/x^2 + 10x + 25

Now, making use of the factorizations, we have ;

(x-5)(x+5)/(x-11) * 4(x-11)/(x+5)(x+5)

Canceling out like factors, we have

= 4(x-5)/(x+5)

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~