Can you help me with the question please thanks I would really appreciate it thank you

a): m=3

b)n=-4

3):x1=4.59779

Step-by-step explanation:

3(m+2)/5=3 solve brackets first

3m+6/5=3  multiply each side by 5

5(3m+6)/5=15

3m+6=15     subtract 6 from each side

3m+6-6=15-6

3m=9

m=9/3=3

b): 8(n-1)/5=3n-4/2 brackets first

8n-8/5=3n-4/2     cross multiplication

2*(8n-8)=5(3n-4)    

16n-16=15n-20   put n together

16n-15n=-20+16

n=-4

3): x^3-2x=88

it is in the form of ax^3+bx^2+cx+d (a=1,b=0,c=1,d=-88)

the polynomial has no rational roots that can be found

to find the value of x1 , find the zero roots of x when y=0

x^3-2x-88=0

x1=4.59779 which lies between 4 and 5( use polynomiol calculator)

x^3-2x-88 by x-4.59779 ( polynomial calculator)

check : (4.59779)^3-2(4.59779)-88= 0( almost zero)

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: