A farmer plans to install solar collection panels to provide winter heating for the livestock. The most efficient panel angle for winter heating in the farm's region is 60° relative to ground level. If
an individual panel is 67 inches (in) long and installed on the ground according to these
instructions, what is the height, in in, of the upper edge above the ground?

58 inches

Step-by-step explanation:

This is a right angled triangle. We would use Trigonometric function of Sine to solve the question

θ = 60°

From the above question, the following values were obtained:

Hypotenuse = 67 inches long

The height in the upper edge above the ground = Opposite side

Sin θ = Opposite/ Hypotenuse

Sin 60° = Opposite/67 inches

Cross Multiply = Sin 60° × 67 inches

= 58.023702054 inches

≈ 58 inches

Therefore, the height in inches of the upper edge is 58 inches

to have more of what you want like money

step-by-step explanation:

save it by not spending on unnecessary stuff and have more

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.