Let x=−1−5i and y=5−i. Find x⋅y.

-10 -24i

Step-by-step explanation:

Note : i=√-1 (imaginary number)

i² = -1

xy

= (−1−5i)(5−i)

= -5 +i -25i +5i²

=-5 +i -25i + 5(-1)

= -5 +i -25i -5

= -5 -5 +i -25i

= -10 -24i

figure c

step-by-step explanation:

hope this .

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.