Form a cubic polynomial whose zeroes are 2, 1/3 and 1/2.

6x³ - 17x² + 11x - 2

Step-by-step explanation:

The cubic polynomial in general form is:

zeroes are

then we can get the polynomial as:

So the required polynomial is:

f(x) = 6x³ - 17x² + 11x - 2

Step-by-step explanation:

Given the zeros x = 2, x = , x = then the factors ar

(x - 2), (x - ), (x - )

By equating the fractional factors to zero we can express them as integer factors, that is

x - = 0 ( multiply through by 3 )

3x - 1 = 0

x - = 0 ( multiply through by 2 )

2x - 1 = 0

Thus the factors are (x - 2), (3x - 1), (2x - 1)

The polynomial is then the product of the factors.

f(x) = (x - 2)(3x - 1)(2x - 1) ← expand last 2 factors using FOIL

     = (x - 2)(6x² - 5x + 1) ← distribute

     = 6x³ - 5x² + x - 12x² + 10x - 2 ← collect like terms

f(x) = 6x³ - 17x² + 11x - 2 ← cubic polynomial

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

89

step-by-step explanation: