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Mathematics, 19.07.2020 08:01 YBNLaLo

Please help! The equation of line AG is y=(b/a+c)x. The midpoint of BC is (a+c, b). Does the midpoint of BC lie on AG? Why or why not?

•no because (b/a+c)b does not equal a+c
•no because (b/a+c)(a+c) does not equal b
•yes because (b/a+c)b=a+c
•yes because (b/a+c)(a+c)=b


Please help!

The equation of line AG is y=(b/a+c)x. The midpoint of BC is (a+c,b). Does the midpo

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Please help! The equation of line AG is y=(b/a+c)x. The midpoint of BC is (a+c, b). Does the midpoi...

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