Find x and y, if
a) (x + y, 3) = (1, x-y)
c) (x-2, y + 1) = (1, 0)

a) x=2, y=-1

Step-by-step explanation:

Make x+y=1 equations number 1 And

x-y=3 another

x+y=1

x=1-y

then substituting the value of x in equations 2

We get,

x-y=3

1-y-y=3

-2y=3-1

y=2/-2

=-1

taking equations 1

x+y=1

x-1=1

x=2

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°