I have a hat that contains six nickels and five pennies. I draw coins from the hat at random, without replacement. Find the probability that after drawing four coins, I have removed at most two pennies from the hat.

53/66

Explanation:

We can use complementary counting to find the probability of picking the outcomes we don't want, and then subtracting that from the whole. The outcomes we don't want are and PPPN.

Probability of picking : 5/11 * 4/10 * 3/9 * 2/8 = 120/7920 = 1/66

Probability of picking PPPN: 5/11 * 4/10 * 3/9 * 6/8 = 360/7290 = 3/66

We can arrange PPPN in four different ways (PPPN, PPNP, PNPP, NPPP) so we need to multiply by 4, giving 12/66.

The total of these two probabilities is 13/66. Subtracting from 66/66, the answer is 53/66.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: