The probability distribution for a
random variable x is given in the table.

0.79

Step-by-step explanation:

I will suppose that this is not a continuos probability, as the individual probabilites add up to 100%.

If you want to obtain the probability that x ≤ 0, then you need to add the probability for the cases x= 0, x = -1, x = -2 etc

This is:

x = 0, p = .16

x = -2, p = .33

x = -3, p = .13

x = -5, p = .17

Then, the probability where x takes a negative value or zero {-5, -3, -2, 0} is:

P = 0.16 + 0.33 + 0.13 + 0.17 = 0.79

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: