Suppose ADequalsISubscript m (the mtimesm identity matrix). Show that for any Bold b in set of real numbers R Superscript m, the equation ABold xequalsBold b has a solution. [Hint: Think about the equation ADBold bequalsBold b.] Explain why A cannot have more rows than columns.

See Explanation

Step-by-step explanation:

(a)For matrices A and D, given that: .

We want to show that , Ax=b has a solution.

If Ax=b

Multiply both sides by D

This means that the system Ax=b has a solution.

(b)Matrix A has a pivot position in each row where each pivot is a different column. Therefore, A must have at least as many columns as rows.

This means A cannot have more rows than columns.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

where's the diagram?

step-by-step explanation: