A sporting goods company is planning to manufacture a commemorative lacrosse ball to demonstrate the importance of lacrosse to Canadian culture. The ball has a
diameter of 10 cm. Determine the dimensions of the cylinder which will package
the lacrosse ball so that it has a maximum volume and minimum surface area.
Calculate the volume and surface area of this cylinder.

Volume of this cylinder = 785.71 Cm³

Surface area of this cylinder = 157.14 Cm²

Step-by-step explanation:

Given:

Height of cylinder = 10 Cm

Radius of cylinder = 10 / 2 = 5 Cm

Find:

Volume of this cylinder.

Surface area of this cylinder

Computation:

Volume of this cylinder = πr²h

Volume of this cylinder = (22/7)(5)²(10)

Volume of this cylinder = 785.71 Cm³

Surface area of this cylinder = 2πr(h+r)

Surface area of this cylinder = 2(22/7)(5)(10+5)

Surface area of this cylinder = 2(22/7)(5)(15)

Surface area of this cylinder = 157.14 Cm²

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.