On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches y = 0. It crosses the y-axis at (0, 6) and goes through (1, 2). Function g (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. It goes through (negative 1, 2) and crosses the y-axis at (0, 6). Which function represents g(x), a reflection of f(x) = 6(one-third) Superscript x across the y-axis?

g(x) = −6(one-third) Superscript x

g(x) = −6(one-third) Superscript negative x

g(x) = 6(3)x

g(x) = 6(3)−x

Step-by-step explanation:

We are given  that

Function f decreases from quadrant  2 to quadrant 1 and approaches  y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

Using the rule then we get

By using

Substitute x=-1

Substitute x=0

Therefore, is true.

the 4th choice is the correct one

step-by-step explanation:

i believe that the answer is

b. y-1=-2(x-4)

hope this !