Assume that trees are subjected to different levels of carbon dioxide atmosphere with 6% of the trees in a minimal growth condition at 340 parts per million (ppm), 13% at 430 ppm (slow growth), 46% at 560 ppm (moderate growth), and 35% at 630 ppm (rapid growth). What is the mean and standard deviation of the carbon dioxide atmosphere (in ppm) for these trees

Mean= 554.4

Standard deviation= 82

Step by step Explanation:

The question want us to calculate a) mean b) standard deviation, while we were given the probability mass function of random variables.

The percentage were of the carbon dioxide were given below;

6% of the trees in a minimal growth condition at 340 = 0.06

13% at 430 ppm = 0.13

46% at 560 ppm = 0.46

35% at 630 ppm= 0.35

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

42.4

step-by-step explanation:

convert to decimal

the population of other specie of birds will decline or other specie of birds will find some alternate source of food to survive.

explanation:

according to the competitive exclusion principle, which is also known as gause's law, two specie living in the same niche and feeding on the same resource cannot co-exist stably.

as we have well studied the theory of natural selection which states that only those organisms survive which have better tendency to compete for food and adapt to the environmental conditions.

coming towards the question, what wi ll happen when one species outcompetes the other for the small fish , the other specie will not get enough food and will start to die or decline in population. eventually either other specie needs to find another alternative food source for itself or migrate at some other location where there is less competition otherwise it will just not exist anymore at that niche.

hope it !