Parallel to the line y= -2x + 4 and passes through point A(2, 4)

Explanation:

Parallel lines have equal slopes, but different y intercepts. The given line y = -2x+4 has a slope of -2. Any line parallel to this will also have a slope of -2.

So m = -2

The unknown line goes through the point (x,y) = (2,4). Which means x = 2 and y = 4 pair up together.

Plug m = -2, x = 2, y = 4 into y = mx+b and solve for b

y = mx+b

4 = -2(2)+b

4 = -4+b

4+4 = b ... adding 4 to both sides

8 = b

b = 8

Since m = -2 and b = 8, we go from y = mx+b to y = -2x+8

Side note: the y intercept of the original equation is 4 while the y intercept of the new equation is 8

y=-2x+8

Step-by-step explanation:

y= -2x + 4 and passes through point A(2, 4)

if a line is parallel then the two lines have the same slope

since the line passes through A(2,4) then

y=-2x+b find b

4=-2(2)+b

b=4+4=8

b=8

y=-2x+8

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.