Mathematics, 17.07.2020 17:01 iiomqjessica

A regular hexagonal prism has a height of 7 cm and base edge length of 4 cm. Identify its lateral area and surface area. HELP ASAP

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Answer from: majestyic1207

Lateral Surface Area = 168 cm^2

Total Surface Area = 209.57 cm^2

Step-by-step explanation:

Given:

There is a regular hexagonal prism with

Height, h = 7 cm

Base edge length, a = 4 cm

To find:

Lateral surface area and total surface area = ?

Solution:

Formula for lateral surface area is given as:

$LSA = \text{Perimeter of Base}\times Height$

Perimeter of a hexagon is given as:

$P = 6 \times Edge\ Length\\\Rightarrow P = 6\times 4=24\ cm$

Now, LSA = 24 $\times$ 7 = 168 cm^2

Total Surface area of prism is given by the formula:

TSA = LSA + B

where B is the area of base.

Base is a regular hexagon, formula for area of a regular hexagon is given by:

$B =6\times \dfrac{\sqrt3}4\times Edge^2\\\Rightarrow B =6\times \dfrac{\sqrt3}4\times 4^2 = 24\sqrt3\ cm^2\\\Rightarrow B = 41.57 cm^2$

So, Total Surface Area = 168 + 41.57 = 209.57 cm^2

So, answer is :

Lateral Surface Area = 168 cm^2

Total Surface Area = 209.57 cm^2

Answer from: Quest

answer:

total cost for tiles and paints is $924.

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

$\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{area of walls and ceiling}=1200+90+120$

$\text{area of walls and ceiling}=1410$

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

$\text{ the total painting cost}=10*(\frac{1410}{25})$

$\text{ the total painting cost}=10*56.4=564$

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

$\text{area of floor} = 40*3\text{ square meters}$

$\text{area of floor} =120\text{ square meters}$

given: 1m squared floor tiles costs $3. so,

$\text{total cost for tiles} = 3*120 = 360$

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

$\text{combined total cost}= 564+360 = 924$

therefore, the combined total cost of tiles and paint is $924.

Answer from: Quest

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7 -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so 14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84 then x = - 0.92 or around -0.9best luck!

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A regular hexagonal prism has a height of 7 cm and base edge length of 4 cm. Identify its lateral ar...