In order for the parallelogram to
be a square, x=?

Step by step explanation

We know that the diagonals of a square bisects it's angles and every angles of square are 90°

m<BCD = 90°

m<BCA = m< DCA = 4x + 17

m<BCA + m<DCA = m <BCD

4x + 17 + 4x + 17 = 90

4x + 4x + 17 + 17 = 90

8x + 34 = 90

8x = 90 - 34

8x = 56

X = 56/8

x = 7

Hope this helps...

Good luck on your assignment...

7

Step-by-step explanation:

The diagonal cuts the angle into 90/2 = 45 degrees.

4x + 17 = 45

4x + 17 - 17 = 45 - 17

4x = 28

(4x)/4 = 28/4

x = 7

answer

106 emergencies

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°