![3^c = \frac{1}{\sqrt{3} } \\Apply -exponent -rule ;\frac{1}{a^b}=a^{-b}\\\frac{1}{\sqrt{3}}=3^{-\frac{1}{2}}\\3^c = 3^{-\frac{1}{2} } \\\mathrm{Apply\:exponent\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}\\3^{-\frac{1}{2}}=3^{-\frac{1}{2}}\\3^c = 3^{-\frac{1}{2} } \\\mathrm{If\:}a^{f\left(x\right)}=a^{g\left(x\right)}\mathrm{,\:then\:}f\left(x\right)=g\left(x\right)\\c = -\frac{1}{2}](/tpl/images/0707/6930/ff946.png)
I am once again in need of mathematical guidance
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Mathematics, 16.07.2020 05:01 akdubgirlp7pe1v
I am once again in need of mathematical guidance
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