If Radhika adds these two numbers and represents the sum on an abacus, and if the beads on the ten's place are 2 and the beads on the one's place are 5, how many beads will be there on the hundreds place?

Explained below.

Step-by-step explanation:

A standard abacus is a traditional method used to perform basic mathematical calculations, such as addition, subtraction, multiplication and division.

There are 5 rods on a standard abacus.

The shape of the abacus has a series of vertical rods on which a number of beads are placed.

Each bead on a particular rod is considered as 1 unit, i.e. if there are three beads on a rod, the value of that rod is 3.

The last rod on an abacus is for the unit's place, the second last rod is for the ten's place, the third last rod is for the hundredth's place, the fourth last rod is for the thousandth's place and the fifth rod is for the ten thousandth's place.

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°