22/55 Marks 46%
The table shows the ages of players on a football team.
Age
Frequency
a) Work out the mean age of the team.
Round your answer to 1 decimal place.
19
2
20
3
21
1
22
4
b) A new player joins the team and raises
the mean age to 22.
23
1
Work out the age of this new player.

Step-by-step explanation:

a) So... To work out the average or mean age we must first calculate the total age.

19 x 2 = 38

20 x 3 = 60

21 x 1  = 21

22 x 4 = 88

23 x 1 = 23

Total = 230

Then... Divide the number of players with this figure

Number of players =  2 + 3 + 2 + 4 + 1 = 11

230/11 = 20.9 is the average age of the players

b) We know the average will now be 22 and we know the number of players is now 12.

So... 22 x 12 = 264 (This will be the new total age of all the players)

We know the previous total was 230

So.. 264-230 = 34 (years old)

Hope this helps

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

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