When you use sine and cosine to solve the value of 0 for the two triangles below, you obtain the same value. Why do you think this happened?

The ratios of the sides of a right triangle are called trigonometric ratios. Three common trigonometric ratios are the sine (sin), cosine (cos), and tangent (tan).

Step-by-step explanation:

In these definitions, the terms opposite, adjacent, and hypotenuse refer to the lengths of the sides.

For example, if we want to recall the definition of the sine, we reference S\blueD{O}\purpleC{H}SOHS, start color #11accd, O, end color #11accd, start color #aa87ff, H, end color #aa87ff, since sine starts with the letter S. The \text{\blueD{O}}Ostart text, start color #11accd, O, end color #11accd, end text and the \text{\purpleC{H}}Hstart text, start color #aa87ff, H, end color #aa87ff, end text help us to remember that sine is \text{\blueD{opposite}}oppositestart text, start color #11accd, o, p, p, o, s, i, t, e, end color #11accd, end text over \text{\purpleC{hypotenuse}}hypotenusestart text, start color #aa87ff, h, y, p, o, t, e, n, u, s, e, end color #aa87ff, end text!

The ratios of the sides of a right triangle are called trigonometric ratios. Three common trigonometric ratios are the sine (sin), cosine (cos), and tangent (tan).

Step-by-step explanation:

what "following statement"?

step-by-step explanation:

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)