Mathematics, 16.07.2020 05:01 santiagodiaz727

what is the minimum sample size required to estimate a population mean with 95% confidence when the desired margin of error is E=1.5? The population standard deviation is known to be 10.75

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Answer from: zoriahmendoza

The minimum sample size is 198

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of 1-0.025 = 0.975 , so z = 1.96

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to estimate a population mean with 95% confidence when the desired margin of error is E=1.5?

This sample size is n.

n is found when M = 1.5.

We have that $\sigma = 1.5$

$M = z*\frac{\sigma}{\sqrt{n}}$

$1.5 = 1.96*\frac{10.75}{\sqrt{n}}$

$1.5\sqrt{n} = 1.96*10.75$

$\sqrt{n} = \frac{1.96*10.75}{1.5}$

$(\sqrt{n})^{2} = (\frac{1.96*10.75}{1.5})^{2}$

n = 197.3

Rounding up

The minimum sample size is 198

Answer from: Quest

wholesale price is the initial price before markup. retail price comes after the markup.

a price of 8 bucks that's marked up by 100% is

formula: initial price + (percent markup in fraction/decimal)(initial price)

8+(1)(8)

8+8

retail price is $16.

Answer from: Quest

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

Lots of points! show all of your work! i need #9-#14 and 12 + 16!

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