The volume of the triangular block is 4 cubic inches. What is the approximate length of y? Round to the nearest 10th of an inch.

2.8 in

Step-by-step explanation:

The volume (V) of the prism is calculated as

V = Ah ( A is the area of the triangular end and h is the length )

A = × x × x = x² , thus

V = x² × x = 4 , that is

x³ = 4 ( multiply both sides by 2 )

x³ = 8 ( take the cube root of both sides )

x = = 2

Using Pythagoras' identity on the right triangle with hypotenuse y, then

y² = x² + x² = 2² + 2² = 4 + 4 = 8 ( take the square root of both sides )

y = ≈ 2.8 in ( to the nearest tenth )

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

idk lol xd

step-by-step explanation:

ez do it yourself lazy