Mathematics, 15.07.2020 03:01 skywil8981
To evaluate the integral 0 (t1/3 − t2/3) dt −1 , first use the property of definite integrals, that is, b (f(x) + g(x)) dx a = b f(x) dx a + b g(x) dx. a Therefore, 0 (t1/3 − t2/3) dt −1 = 0 t1/ dt −1 ---Select--- 0 t /3 dt. −1
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To evaluate the integral 0 (t1/3 − t2/3) dt −1 , first use the property of definite integrals, that...
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