A nursing student is planning his schedule for next quarter. He needs to take three courses and one must be statistics. For his other courses, he can choose one of two science classes and one of three social sciences classes. What is the probability that his social sciences class is not Economics?

0.66

Step-by-step explanation:

He must choose 2 courses.

The options are:

one of two science classes

one of three social sciences classes.

For the first class selection we do not have any restriction, so that selection can be ignored.

Now, we can assume that one of the 3 social sciences is economics, so we have 2 classes that are not economics.

Then, the probability that he does not select economics (if the selections are at random) is equal to the number of classes that are not economics divided the total number of classes:

p = 2/3 = 0.66

sine

step-by-step explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol