The length of a rectangle is twice its width. The perimeter is 30. Find its dimensions

Step-by-step explanation:

given,

perimeter (p)=30

let the length be x and breadth be x÷2 (as the length is twice of its breadth)

now, perimeter (p)=30

or, 2(l+b)=30

or, 2(x+x/2)=30

or, 6x/2=30

or, 3x=30

therefore the value of x is 10.

the dimensions are,

so, length (l)=10 breadth (b) =10/2=5...ans

hope it will help uh.

do you have the measurements?

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!