Help me answer this question please with full working

a. y = x^2 + 10

b. when x=5,   y  = 35

c. when y = 26,   x =  +4 or -4

Step-by-step explanation:

Given

y = k (x^2/2 + 5), and

(2,14) is on the curve.

Solution:

Substitute x=2 and y=14 in the above equation

14 = k (2^2/2 + 5)

14 = k (2+5)

14 = 7k

k = 14/7 = 2

a. equation connecting x and y is

   y = 2 (x^2/2 + 5), or

   y = x^2 + 10

b. when x=5

   y = 5^2 + 10 = 25 + 10 = 35

c. when y = 26

  26 = x^2 + 10

  x^2 = 26-10 = 16

  x= sqrt(16) = +4 or -4

the function makes a strait line horizontally with no x intercept but a y intercept at 9.