Use the given data to construct a confidence interval for the population proportion of the requested level. x=52, n=72, confidence level 99.9% Round the answer to at least three decimal places.

The 99.9% confidence interval for the population proportion is (0.548, 0.896).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

99.9% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 99.9% confidence interval for the population proportion is (0.548, 0.896).

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.