Answer for all please

a)

mean of the Standard normal distribution is μ = 0

Standard deviation of the Standard normal distribution σ = 1

b) P( Z < 1.96) = 0.9744

c)

P( - 0.41 < Z) = 0.6591

d) h = 0.3

Step-by-step explanation:

Step(i):-

a)

Given X be a continuous random variable in Normal distribution

The Normal distribution for μ = 0 and σ = 1 is known as Standard normal distribution

mean of the Standard normal distribution is μ = 0

Standard deviation of the Standard normal distribution σ = 1

b)

P( Z < 1.96) = 0.5 + A(1.96)

                  = 0.5 + 0.4744

                  = 0.9744

P( Z < 1.96) = 0.9744

c)

P( - 0.41 < Z) = P(Z > -0.41)

                    = 0.5 +A(-0.41)   (∵ A(-0.41) = A(0.41)

                    = 0.5 + 0.1591

                    = 0.6591

P( - 0.41 < Z) = 0.6591

d)i)  If  h >0

      P( z < h) = 0.20

 ⇒  0.5 +A(z) = 0.20

 ⇒      A(Z) = 0.20 - 0.5

⇒      A(Z) = - 0.3

          h = -0.3

if h < 0

   P( z < h) = 0.20

 ⇒  0.5 -A(z) = 0.20

 ⇒      A(Z) =0.5 - 0.2

⇒      A(Z) =  0.3

          h = 0.3

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step-by-step explanation:

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without