With 98% confidence interval and n = 25. Find left critical value for Zinterval. 0 -2.492
0 -2.05
0 -2.797
-2.326

And , the degrees of freedom are given by:

Then the critical value using the t distribution with 24 degrees of freedom is:

And the best solution would be:

0 -2.492

Step-by-step explanation:

For this problem we know that the sample size is n = 25. The confidence level is 98% or 0.98 then the significance would be:

And , the degrees of freedom are given by:

Then the critical value using the t distribution with 24 degrees of freedom is:

And the best solution would be:

0 -2.492

19.

step-by-step explanation:

you add the 9 in the tens column since it is a single digit and 9 plus zero is 9 so it is 19