With 98% confidence interval and n = 25. Find left critical value for Zinterval. 0 -2.492
0 -2.05
0 -2.797
-2.326

And , the degrees of freedom are given by:

Then the critical value using the t distribution with 24 degrees of freedom is:

And the best solution would be:

0 -2.492

Step-by-step explanation:

For this problem we know that the sample size is n = 25. The confidence level is 98% or 0.98 then the significance would be:

And , the degrees of freedom are given by:

Then the critical value using the t distribution with 24 degrees of freedom is:

And the best solution would be:

0 -2.492

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3