A restaurant offers 6 choices of appetizer, 8 choices of a main meal, and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses. Assuming all choices are available, how many different possible meals does the restaurant offer?

377 choices

Step-by-step explanation:

From the above question, we are told that

A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses.

Let us represent each choice by :

A = Appetizer = 6

M = Main meal = 8

D = Dessert = 5

a) The combination of the 3 choices together

AMD=6 × 8 × 5=240

b) AM= Appetizer and Main meal

= 6 × 8 = 48

c) AD= Appetizer and Dessert

= 6 × 5 = 30

d) MD = Main meal × Dessert

= 8 × 5 = 40

e) A,M,D (each alone)=

Appetizer + Main meal + Dessert

= 6 + 8 + 5

= 19

Assuming all choices are available, how many different possible meals does the restaurant offer?

This is calculated as:

AMD + AM + AD + MD + A,M,D

240 + 48 + 30 + 40 + 19

= 377 choices

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

answer: they are supplementary angles

step-by-step explanation: 161+19=180. supplementary angles equal 180 degrees