For the rational function f(x)=x-2/3x^2+x-2, fill in the points on the graph at the function value f(x)=2.

  (-2/3, 2), (1/2, 2)

Step-by-step explanation:

A graphing calculator can show you those points: (-2/3, 2), (1/2, 2).

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Put the given value in the equation and solve for x.

  2 = f(x)

  2 = (x -2)/(3x^2 +x -2)

  2(3x^2 +x -2) -(x -2) = 0 . . . . . multiply by the denominator; put in standard form

  6x^2 +x -2 = 0 . . . . . collect terms

  (3x +2)(2x -1) = 0 . . .  factor

Solutions are values of x that make the factors zero:

  x = -2/3, x = 1/2

Then the points on the graph are (-2/3, 2) and (1/2, 2).

the answer on e2020 is

10

4/5

3/5

4/3

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?