Identify an equation in point-form for the line perpendicular to y=-1/3x-6 that pass through -1,5

y - 5 = 3(x + 1).

Step-by-step explanation:

y = -1/3x - 6

The slope of this line is -1/3 so the slope of the perpendicular line to it is -1/-1/3

= 3.

Using the point-slope form of a straight line:

y - y1 = m(x - x1)  where m = the slope and (x1, y1) is a point on the line:

Here m = 3 and (x1, y1) is (-1, 5) so we have:

y - 5 = 3(x - (-1))

y - 5 = 3(x + 1).

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3