PLEASE HELP ASAP THANKS!! A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses. Assuming all choices are available, how many different possible meals does the restaurant offer?

377 meals

Step-by-step explanation:

If you choose to have all three courses, then there are 6 choices for the first course, 8 for the second, and 5 for the last, making a total of 6*8*5=240 different possible meals.

If you choose two courses, then there are 3 options. You can pick appetizer and main meal, which would give you 6*8=48 possibilities. You can pick main meal and dessert, which would give you 8*5=40 possibilities. Finally you can pick appetizer and desert, which would give you 6*5=30 possibilities. In total these are 118 different possible meals with two courses.

Finally, you could choose 1 course, which would give you 6+8+5=19 different meals.

In total, this is 240+118+19=377 meals

y= -

the answer is a

step-by-step explanation: