to solve the system of equations below, Zach isolated x^2 in the first equation and then substituted it into the second equation. What was the resulting equation. (x^2 y^2=25; (x^2/15-y^2/9=1 A. x^2/16-y^2-25/9=1 B. x^2/16-25-y^2/9=1 C.25-y^2/16-y^2/9=1 D. y^2-25/16-y^2/9=1

Step-by-step explanation:

Given the equations x^2 + y^2=25 ...1 and x^2/15-y^2/9=1,.. 2 to solve the systam of equation we will make  x^2 the subject of the formula from the first equation and substitute it into the second equation as shown;

Fom 1; x² = 25-y²... 3

Substituting equation 3 into 2 to get the resulting equation will give;

x²/15-y²/9=1

25-y²/15 - y²/9 = 1

The final expression gives the required equation.

c) yes, because of asa or aas

i cant answer this, theres no table. sorry man

step-by-step explanation: