Suppose that a computer chip company has just shipped 10 comma 000 computer chips to a computer company. Unfortunately, 40 of the chips are defective. (a) Compute the probability that two randomly selected chips are defective using conditional probability. (b) The probability that the first randomly selected chip is defective is StartFraction 40 Over 10 comma 000 EndFraction equals 0.004 equals 0.4 % . Compute the probability that two randomly selected chips are defective under the assumption of independent events. (a) The probability is nothing.

approx 0,000016 or 0,0016%

Step-by-step explanation:

The probability that first selected chip is defective is 40/10000=4/1000

So only 39 defective chps left amoung 9999 chips.

So the probability that second randomly selected chip is defective as well is

39/9999= 13/3333=approx 0.004

The probability that both chips are defective is

P(both=defective)=0.004*0.004= 0.000016 or 0.0016%

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40

i think it might be a but you might want a second opinion