Rearrange the following steps in the correct order to locate the last occurrence of the smallest element in a finite list of integers, where the integers in the list are not necessarily distinct. Rank the options below.
if min > ai then
procedure last smallest a1,a2,,an: integers)
return location
min = a1 and location = 1
min ai and location = i
for i = 2 to n

procedure last smallest a1,a2,,an: integers)

min = a1 and location = 1

for i = 2 to n

if min > ai then

min ai and location = i

return location

Step-by-step explanation:

The first step is to define the function or procedure last_smallest; This is done by this line

procedure last smallest a1,a2,,an: integers)

The next step is to initialize two variables to 1; The first variable is the min which represents minimum while the second is location, which represents its location

min = a1 and location = 1

The next is to iterate from the second element to the last

for i = 2 to n

This line checks for the smallest element; if the following conditional statement returns true, then:->

if min > ai then

->It assigns appropriate values to min and location

min ai and location = i

The last step returns the assigned location of the element

return location

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square pyramid

step-by-step explanation:

square prism looks like nothing like that

triangular prism has a rectangular base instead of a square base

tetrahedron has a triangular base