Find a missing numerators in each of the following problems. a. 10/15 = /60 b. /180 = 4 / 9 c. 7/11 = /121 d. /144 = 2/6

  a) 40

  b) 80

  c) 77

  d) 48

Step-by-step explanation:

To find the missing numerator, multiply the equation by the denominator of the fraction with the missing numerator.

a) (10/15)(60) = (x/60)(60)

  40 = x

__

b) (x/180)(180) = (4/9)(180)

  x = 80

__

c) (7/11)(121) = (x/121)(121)

  77 = x

__

d) (x/144)(144) = (2/6)(144)

  x = 48

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

hello, there is a new name in town and that's the human spider!

answer: d.) the total number of protons and neutrons is 15

merry christmas!

~

your friendly neighborhood human spider! .