Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If women's weights are normally distributed with a mean of 173.6 lb and a standard deviation of 49.8 lb, what percentage of women have weights that are within those limits? Are many women excluded with those specifications?

And we can find this probability with this difference and using the normal standard table:

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

Where and

We are interested on this probability

And the best way to solve this problem is using the normal standard distribution and the z score given by:

If we apply this formula to our probability we got this:

And we can find this probability with this difference and using the normal standard table:

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5