Find the angle between the given vectors to the nearest tenth of a degree. u = <2, -4>, v = <3, -8>

You can use

cos(theta) = u · v / ║u║║v║

that will come out to:

u = 2 x (-4) = -8

v = 3 x (-8) = - 24

u · v = -16

║u║ =  =

║v║ =

cos(theta)  = -16/2

and to find (theta), you can now do

theta = (cos^-1) ( -16/2 )

I don't have a calculator, but you can solve that final problem to find theta

p = 6s

step-by-step explanation:

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