Complete the square to rewrite y= x2 - 6x + 2 in vertex form. Then state whether the vertex is a maximum or a minimum and give its coordinates.

see explanation

Step-by-step explanation:

Given

y = x² - 6x + 2

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² - 6x

y = x² + 2(- 3)x + 9 - 9 + 2

  = (x - 3)² - 7 ← in vertex form

with vertex = (3, - 7 ) and a = 1

Since a > 0 then vertex is a minimum

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6