Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y2 Is the student’s work correct? No, she did not multiply –6y2 by 2 correctly. No, she did not add 3y2 and –12y2 correctly. No, she did not use the distributive property correctly. Yes, she multiplied the binomials correctly.