Find the solution to the system of equation select all that apply y=x^2-4 y=2x-5

x = 1, y = -3

Explanation: Use the method of substitution we get:

y = x^2-4
y = 2x-5

By substitute:

x^2-4=2x-5

Then we can solve the equation for x

x^2-4-2x+5=0
x^2-2x+1=0

Now solve the quadratic equation by factoring we get:

x^2-2x+1=0
(x-1)(x-1)=0
x-1=0
x = 1

Now that we have found x we can substitute x to the equation:

y = x^2-4
y=1^2-4
y=-3

y=2x-5
y=2(1)-5
y=-3

So there you have it :)