P(x) has factors (x-2), (x+1), and (x-3). Decide if there is only one polynomial that has these factors. Justify your conclusions

P(x)= x³ +2x² -5x -6

It's only the above polynomial that have the factors (x-2), (x+1), and (x-3).

Step-by-step explanation:

P(x) has factors of (x-2), (x+1), and (x-3)

Let's determine the polynomial p(x)

(x-2) (x+1) (x-3)= (x² +x-2x-2)(x-3)

(x-2)(x+1)(x-3)= (x²-x-2)(x+3)

(x²-x-2)(x+3)= x³ + 3x² -x² -3x -2x -6

(x²-x-2)(x+3)= x³ +2x² -5x -6

P(x)= x³ +2x² -5x -6

As we can see the polynomial p(x) was gotten from the multiplication of the the three factors.

So it's only the polynomial that has these factors.

The polynomial that has the factors

(x-2), (x+1), and (x-3) is polynomial p(x) only.

where's the diagram?

step-by-step explanation:

the height of the surface increases from the center out to the sides of the road

it is c!