Find the area of the figure. A rectangle topped by a triangle. The rectangle has length 6 yards and width 4 yards. The triangle has side lengths 3 yards and 4 yards.
a.
48 sq. yd
b.
60 sq. yd
c.
30 sq. yd
d.
42 sq. yd

area of figure = area of rectangle + area of triangle

area of rectangle= length × width

6×4

24yd²

area of triangle= 1/2×base×height

1/2×3×4

3×2

=6yd²

area of figure= 24+6

= 30yd²

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.