Find the x- and y-intercepts of the function f(x) = log(2x + 1) − 1. The x-intercept of the function f(x) = log(2x + 1) − 1 is

. Its y-intercept is

.

The y-intercept is -1

The x-intercept is 4.5

Step-by-step explanation:

We have the following equation:

f(x) = log(2x+1) - 1

The y intercept is the value of f(x) when x is equal to 0, so replacing x by 0 and solving for f(x), we get:

f(0) = log(2*0 + 1 ) -1

f(0) = log(1) - 1

f(0) = 0 - 1 = -1

Additionally, the x-intercept is the value of x when f(x) is equal to 0. So, replacing f(x) by 0 and solving for x, we get:

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°