A mortar shell is fired with a muzzle speed of 300 ft/sec. Find the angle of elevation of the mortar if the shell strikes a target located 1500 ft away. Round your answer to 2 decimal places.

Angle of elevation = 4.37°

Step-by-step explanation:

Velocity of the mortar shell = 300ft/sec

Distance covered= 1500ft

Range = U²sin2tita/g

But range= distance

Range = 1500ft

U = velocity

g = acceleration due to gravity

Tita = angle of projection of elevation

1500 = 300²sin(2tita)/9.87

(1500*9.87)/90000= sin2tita

0.1645 = sin2tita

Sin^-1 0.1645 = 2tita

9.4682 = 2tita

total = 9.4682/2

tita = 4.3741°

To two decimal place= 4.37°

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13