A survey showed that 76% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 8 adults are randomly selected, find the probability that at least 7 of them need correction for their eyesight. Is 7 a significantly high number of adults requiring eyesight correction?

as probability of this is higher than 0.05 level this is not significantly high number .

Step-by-step explanation:

we have here a binomial distribution with the following data:

p = 0.76 and n = 8

therefore probability that a least 7 of the 8 adults require eyesight correction is P (X> = 7)

 P (X> = 7) = P (X = 7) + P (X = 8) = nCr * (p) ^ (n) * (1-p) ^ (n-r)

= (8C7) * (0.76) ^ 8 * (0.24) ^ (8-7) + (8C8) * (0.76) ^ 8 * (0.24) ^ (8-8)

nCr = n! / (r! * (n-r)!

replacing:

(8C7) = 8! / (7! * (8-7)!) = 8

(8C8) = 8! / (8! * (8-8)!) = 1

P (X> = 7) = 8 * 0.0267 + 1 * 0.11130 = 0.325

as probability of this is higher than 0.05 level this is not significantly high number .

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without