The perimeter (distance around the triangle) of a triangular lot is 73 meters with Sides A, B, and C. Side A is 16 meters, Side B is twice the length of Side C. Find the length of Side C.

Brainliest please

Step-by-step explanation:

perimeter is to add all sides

73m= 16+B+C

{ use algebra}

C is a, B is twice C, hence 2a

a+2a(+16)=73

3a=73-16= 57

3a=57, divide

a= 19

B=19×2= 38m

C=19m

C is 19m

C = 19 m

Step-by-step explanation:

Side B is twice the length of Side C.

B = 2C (I)

Perimeter = 73 m

A + B + C = 73

A + 2C + C = 73  {from (I)}

16 + 3C = 73

3C = 73 - 16

3C = 57

C = 57/3

C = 19 m

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

entering that problem on the tube might get you an answer